y^'=6x^2y^2

解答

y^{^{'}} = 6 x^{2} y^{2}

y = - \frac{1}{2 x ^{3} + c _{1}}

求解步骤

y^{'} (x) = 6 x^{2} y^{2}

求解可分离方程:

y = - \frac{1}{2 x ^{3} + c _{1}}

y = - \frac{1}{2 x ^{3} + c _{1}}

\frac{d y}{d x} + y sec (x) = sec (x)

(1 + 2 y) d x + (4 + x^{2}) d y = 0

2 (y - 1) y^{^{'}} - 3 t^{2} - 34 t = 2

\frac{4 d y}{d x} + y = 2

H (x) (x)^{2} x^{2} d x = 2 x^{2} d H (x)