y^'+y/5 =y^{-3}

Lösung

y^{^{'}} + \frac{y}{5} = y^{- 3}

y = 4 - e^{\frac{- 4 t - c _{1}}{5}} + 5, y = - 4 - e^{\frac{- 4 t - c _{1}}{5}} + 5

Schritte zur Lösung

y^{'} (t) + \frac{y}{5} = y^{- 3}

Solve separable ODE:

y = 4 - e^{\frac{- 4 t - c _{1}}{5}} + 5, y = - 4 - e^{\frac{- 4 t - c _{1}}{5}} + 5

y = 4 - e^{\frac{- 4 t - c _{1}}{5}} + 5, y = - 4 - e^{\frac{- 4 t - c _{1}}{5}} + 5

y^{^{'}} = e^{(x - 2 y)}

2 y y^{^{'}} = x e^{x}

y^{^{'}} = x e^{5 x - 3 y}, y (0) = 2

\frac{d x}{d t} = 2 x

x \frac{d y}{d x} - y = y^{2}