f(x)=(x^3+4x+2)^3f^'(x)

Lösung

f (x) = (x^{3} + 4 x + 2)^{3} f^{^{'}} (x)

f (x) = e^{\int \frac{1}{( x ^{3} + 4 x + 2 ) ^{3}} d x}

Schritte zur Lösung

f (x) = (x^{3} + 4 x + 2)^{3} f^{'} (x)

Solve separable ODE:

f (x) = e^{\int \frac{1}{( x ^{3} + 4 x + 2 ) ^{3}} d x}

f (x) = e^{\int \frac{1}{( x ^{3} + 4 x + 2 ) ^{3}} d x}

y^{^{'}} + e^{y} x = 0

\frac{d x}{d t} = 20 - 0.6 \cdot x

\frac{d y}{d x} = y (4 x^{2} + 3)

\frac{d y}{d x} = e^{2 x - y}, y (0) = 0

d y = x (2 y d x - x d y), y (2) = 3