y^'=y^{2/3},y(0)=0

Lösung

y^{^{'}} = y^{\frac{2}{3}}, y (0) = 0

y = \frac{t ^{3}}{27}

Schritte zur Lösung

y^{'} (t) = y^{\frac{2}{3}}

Solve separable ODE:

y = \frac{t ^{3}}{27}

y = \frac{t ^{3}}{27}

(x^{2} + 1) y^{^{'}} + x y = 0

\frac{d P}{d t} = a - b P (t)

\frac{d y}{d x} = \frac{( x y ^{3} )}{1 + x ^{2}}

\frac{1}{x} y^{^{'}} - y - 1 = 0

y^{^{'}} - 2 y = 10, y (0) = 0