y^'=-(y^2)/x

Lösung

y^{^{'}} = - \frac{y ^{2}}{x}

y = - \frac{1}{- ln ( x ) + c _{1}}

Schritte zur Lösung

y^{'} (x) = - \frac{y ^{2}}{x}

Solve separable ODE:

y = - \frac{1}{- ln ( x ) + c _{1}}

y = - \frac{1}{- ln ( x ) + c _{1}}

y^{^{'}} + 4 y = 3, 2 x y (0) = 2

(1 + 2 x) \frac{d y}{d x} = \frac{4 x ^{3}}{y}

2 x y y^{^{'}} - y^{2} = 1

y^{^{'}} = (x + 1) y^{2}, y (0) = \frac{1}{2}

u^{^{'}} = 5 e^{9 x - H (x)}