y^'sec(x)=4y^2,y((5pi)/2)= 1/5

Lösung

y^{^{'}} sec (x) = 4 y^{2}, y (\frac{5 π}{2}) = \frac{1}{5}

y = - \frac{1}{4 sin ( x ) - 9}

Schritte zur Lösung

y^{'} (x) sec (x) = 4 y^{2}

Solve separable ODE:

y = - \frac{1}{4 sin ( x ) - 9}

y = - \frac{1}{4 sin ( x ) - 9}

(2 x + 3) y^{^{'}} = y + 4

y^{^{'}} = \frac{- ( 3 y ^{2} + 1 ) x}{x ^{2} + 1}, y (0) = 1

y \cdot y^{^{'}} = x

\frac{d y}{d t} = y - y t^{2}

d t = \frac{200 d m}{1600 - 3 m}