y^'=2y+1,y(0)=1

Lösung

y^{^{'}} = 2 y + 1, y (0) = 1

y = \frac{3 e ^{2 t}}{2} - \frac{1}{2}

Schritte zur Lösung

y^{'} (t) = 2 y + 1

Solve separable ODE:

y = \frac{3 e ^{2 t}}{2} - \frac{1}{2}

y = \frac{3 e ^{2 t}}{2} - \frac{1}{2}

y^{^{'}} + 3 y = 7, y (0) = 1

2 y d y = (x^{2} + 4) d x

x \frac{d y}{d x} + y = 1 y^{2}

\frac{d y}{d x} = \frac{5 y}{4 x ^{2}}

y^{^{'}} + 33 \frac{y}{x} = 0