(x+1)dx= 1/(-y^2)dy

Lösung

(x + 1) d x = \frac{1}{- y ^{2}} d y

y = - \frac{2}{- x ^{2} - 2 x + c _{1}}

Schritte zur Lösung

(x + 1) d x = \frac{1}{- y ^{2}} d y

Solve separable ODE:

y = - \frac{2}{- x ^{2} - 2 x + c _{1}}

y = - \frac{2}{- x ^{2} - 2 x + c _{1}}

y^{^{'}} = \frac{( y ^{2} + 1 )}{( x ^{2} + 1 )}

(2 t - 1) y^{^{'}} - 4 y = 0

f (x) f^{^{'}} (x) = x x^{3} - x x^{2} - 6 xx

f^{^{'}} (x) = f (x)^{- 1} (x)

x y^{2} y^{^{'}} = x + x^{3}