(t^3-12t+27)(dy)/(dt)=y

Lösung

(t^{3} - 12 t + 27) \frac{d y}{d t} = y

y = e^{\int \frac{1}{t ^{3} - 12 t + 27} d t}

Schritte zur Lösung

(t^{3} - 12 t + 27) \frac{d y}{d t} = y

Solve separable ODE:

y = e^{\int \frac{1}{t ^{3} - 12 t + 27} d t}

y = e^{\int \frac{1}{t ^{3} - 12 t + 27} d t}

\frac{d y}{d x} = y, y > 0

7 x y \frac{d y}{d x} = 2, y > 0

sin (y) y^{^{'}} = x cos (y)

10 y y^{^{'}} = x, y (10) = 9

\frac{d y}{d x} = 1 - 0.4 y