(dy)/(dx)2xy=1

解答

\frac{d y}{d x} 2 x y = 1

y = ln (x) + c_{1}, y = - ln (x) + c_{1}

求解步骤

\frac{d y}{d x} 2 x y = 1

求解可分离方程:

y = ln (x) + c_{1}, y = - ln (x) + c_{1}

y = ln (x) + c_{1}, y = - ln (x) + c_{1}

\frac{d Q}{d x} = 15 - 3 \frac{Q}{400}

e^{t} y^{^{'}} = (1 + y^{2}) t

x^{2} y^{^{'}} = y^{2}, y (1) = - 1

y^{^{'}} = \frac{x}{y}, y (0) = - 3

\frac{d}{d t} (H (t)) = 4 - 0.5 H (t), H (0) = 0