y^'=(3t^2y)/(y+1),y(2)=1

Lösung

y^{^{'}} = \frac{3 t ^{2} y}{y + 1}, y (2) = 1

y + ln (y) = t^{3} - 7

Schritte zur Lösung

y^{'} (t) = \frac{3 t ^{2} y}{y + 1}

Solve separable ODE:

y + ln (y) = t^{3} - 7

y + ln (y) = t^{3} - 7

\frac{d x}{d t} = e^{- x} cos (3 t), x (0) = 1

x^{2} cos^{2} (y) d x + x^{3} d y = 0

\frac{d x}{d t} = \frac{4}{x}

2 x^{^{'}} + x = 0

\frac{d y}{d x} sin (2 y) - cos (x) = 0