y^'=(11cos(11x))/(3+2y),y(0)=-1

Lösung

y^{^{'}} = \frac{11 cos ( 11 x )}{3 + 2 y}, y (0) = - 1

y = \frac{- 3 + 4 sin ( 11 x ) + 1}{2}

Schritte zur Lösung

y^{'} (x) = \frac{11 cos ( 11 x )}{3 + 2 y}

Solve separable ODE:

y = \frac{- 3 + 4 sin ( 11 x ) + 1}{2}

y = \frac{- 3 + 4 sin ( 11 x ) + 1}{2}

\frac{d y}{d x} = (2 x) (y)

y^{^{'}} = \frac{1}{2} y^{3}

y^{^{'}} \cdot tan (x) - y = - 2

\frac{d y}{d x} + 6 y = 1

y^{^{'}} = 2 x cos^{2} (y)