y^'+y(1/x-3/4)=0

Lösung

y^{^{'}} + y (\frac{1}{x} - \frac{3}{4}) = 0

y = \frac{e ^{\frac{3 x + c _{1}}{4}}}{x}

Schritte zur Lösung

y^{'} (x) + y (\frac{1}{x} - \frac{3}{4}) = 0

Solve separable ODE:

y = \frac{e ^{\frac{3 x + c _{1}}{4}}}{x}

y = \frac{e ^{\frac{3 x + c _{1}}{4}}}{x}

d v = e^{2 x} d x

(1 + y^{2}) d x - d y = 0

\frac{1}{2} y y^{^{'}} = t^{3}, y (0) = 2

(x^{2} + 9) d y = (2 x - 8 x y) d x

y^{^{'}} = x y^{2} + x