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Popular >

y^'= 1/(e^y)

Solution

y^{^{'}} = \frac{1}{e ^{y}}

Solution

y = ln (t + c_{1})

Solution steps

y^{'} (t) = \frac{1}{e ^{y}}

Solve separable ODE:

y = ln (t + c_{1})

y = ln (t + c_{1})

Popular Examples

y^'=e^{(2+0)x+(1+5)y}

y^{^{'}} = e^{(2 + 0) x + (1 + 5) y}

dy=sqrt(e^{2y)}+1dx

d y = e^{2 y} + 1 d x

(dy)/(dx)y=e^{-x^2}cos(x)

\frac{d y}{d x} y = e^{- x^{2}} cos (x)

(dy)/(dx)=e^xsin(2y)

\frac{d y}{d x} = e^{x} sin (2 y)

(dy)/(dx)= x/y ,y(3)=5

\frac{d y}{d x} = \frac{x}{y}, y (3) = 5

Frequently Asked Questions (FAQ)

What is the solution for y^'= 1/(e^y) ?
The solution for y^'= 1/(e^y) is y=ln(t+c_{1})