tx^'=-t^2x^3

Lösung

t x^{^{'}} = - t^{2} x^{3}

x = - \frac{1}{- t ^{2} + c _{1}}, x = - - \frac{1}{- t ^{2} + c _{1}}

Schritte zur Lösung

t x^{'} (t) = - t^{2} x^{3}

Solve separable ODE:

x = - \frac{1}{- t ^{2} + c _{1}}, x = - - \frac{1}{- t ^{2} + c _{1}}

x = - \frac{1}{- t ^{2} + c _{1}}, x = - - \frac{1}{- t ^{2} + c _{1}}

x^{^{'}} = x (t^{2} - 1) (t^{2} - 9), x (0) = 1

y^{^{'}} = \frac{t ( 4 y - y ^{2} )}{3}

\frac{d y}{d x} y = ln (2 - x - x^{2})

\frac{d P}{d t} = P (7 - P) - \frac{49}{4}

y^{^{'}} + \frac{3}{x} y = 0