y^'+3/x y= 1/x

Lösung

y^{^{'}} + \frac{3}{x} y = \frac{1}{x}

y = \frac{c _{1}}{3 x ^{3}} + \frac{1}{3}

Schritte zur Lösung

y^{'} (x) + \frac{3}{x} y = \frac{1}{x}

Solve separable ODE:

y = \frac{c _{1}}{3 x ^{3}} + \frac{1}{3}

y = \frac{c _{1}}{3 x ^{3}} + \frac{1}{3}

8 t y + e^{t} y^{^{'}} = \frac{y}{t ^{2} + 64}

y y^{^{'}} - 4 y^{^{'}} - 5 y = 125

(x + 1) (x - 2) \frac{d y}{d x} + y = 0

3 (16 + y^{2}) d x + 2 x y d y = 0

(y + x y) + (x - x y) y^{^{'}} = 0