2(y-4x^2)dx+xdy=0

解答

2 (y - 4 x^{2}) d x + x d y = 0

y = 2 x^{2} + \frac{c _{1}}{x ^{2}}

求解步骤

2 (y - 4 x^{2}) d x + x d y = 0

求解线性方程:

y = 2 x^{2} + \frac{c _{1}}{x ^{2}}

y = 2 x^{2} + \frac{c _{1}}{x ^{2}}

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