7y^'-2y-80=6y^'

Lösung

7 y^{^{'}} - 2 y - 80 = 6 y^{^{'}}

y = e^{2 t + c_{1}} - 40

Schritte zur Lösung

7 y^{'} (t) - 2 y - 80 = 6 y^{'} (t)

Solve separable ODE:

y = e^{2 t + c_{1}} - 40

y = e^{2 t + c_{1}} - 40

(x^{2} - 2 x^{2}) d x + x y d y = 0

x^{^{'}} + x^{2} = 1

\frac{d y}{d t} = (t + 1) y, y (0) = \frac{1}{2}

\frac{d y}{d x} = - 1 y + 3 y

y^{^{'}} = 3 x^{2} \cdot y^{3}, y (0) = - 5