y^'=2e^{x-y}

Lösung

y^{^{'}} = 2 e^{x - y}

y = ln (2 e^{x} + c_{1})

Schritte zur Lösung

y^{'} (x) = 2 e^{x - y}

Solve separable ODE:

y = ln (2 e^{x} + c_{1})

y = ln (2 e^{x} + c_{1})

y^{^{'}} = \frac{t ^{3} y ^{2}}{t ^{4} + e}, y (0) = 1

x y^{2} \frac{d y}{d x} = 2

y^{^{'}} + y \cdot tan (x) = 0

y^{^{'}} = e^{4 x - 3 y}, y (0) = 0

d y + y tan (x) d x = 0