(dy)/(dx)=xy^2+x

Lösung

\frac{d y}{d x} = x y^{2} + x

y = tan (\frac{x ^{2}}{2} + c_{1})

Schritte zur Lösung

\frac{d y}{d x} = x y^{2} + x

Solve separable ODE:

y = tan (\frac{x ^{2}}{2} + c_{1})

y = tan (\frac{x ^{2}}{2} + c_{1})

\frac{d y}{d x} = - 9 x^{2} y

y^{4} y^{^{'}} - 3 y^{5} = 0

\frac{d x}{d t} = 8 x t^{3}

y^{^{'}} = \frac{t y ^{2}}{t ^{2} + 1}, y (0) = 1

d x + y^{2} d y = 0