x^'+x=1

Lösung

x^{^{'}} + x = 1

x = - e^{- t - c_{1}} + 1

Schritte zur Lösung

x^{'} (t) + x = 1

Solve separable ODE:

x = - e^{- t - c_{1}} + 1

x = - e^{- t - c_{1}} + 1

y^{^{'}} = 5 y - 15, y (0) = 9

(3 x + 7) + (3 y - 3) y^{^{'}} = 0

\frac{d y}{d x} + e^{x} y = 2 e^{x}, y = 1, x = 0

\frac{d y}{d x} - (y - 1)^{2} = 0

x y y^{^{'}} = (1 + x^{2})