d/(dθ)(r(θ))+r(θ)tan(θ)=tan(θ)

解

\frac{d r}{d θ} + r tan (θ) = tan (θ)

r = \frac{tan ( θ )}{1 + tan ( θ ) θ}; 1 + tan (x) x \neq = 0

解答ステップ

\frac{d}{d θ} (r θ) + r θ tan (θ) = tan (θ)

\frac{d}{d θ} (r θ) = r

r + r θ tan (θ) = tan (θ)

r + r θ tan (θ) = tan (θ) : r = \frac{tan ( θ )}{1 + tan ( θ ) θ}; 1 + tan (x) x \neq = 0

r = \frac{tan ( θ )}{1 + tan ( θ ) θ}; 1 + tan (x) x \neq = 0