2xy=-(x^2-1)y^'

Lösung

2 x y = - (x^{2} - 1) y^{^{'}}

y = \frac{c _{1}}{x ^{2} - 1}

Schritte zur Lösung

2 x y = - (x^{2} - 1) y^{'} (x)

Solve separable ODE:

y = \frac{c _{1}}{x ^{2} - 1}

y = \frac{c _{1}}{x ^{2} - 1}

\frac{d y}{d t} + y = y t e^{t + 2}

(y^{2} - y) d x + x d y = 0

y y^{^{'}} = x^{2} e^{2 x + 2 y} sin (3 x)

x \cdot \frac{d y}{d x} = 2 + 3 y

5 y d x = 3 x d y