y^'=8y-5

Lösung

y^{^{'}} = 8 y - 5

y = \frac{e ^{8 t + c_{1}}}{8} + \frac{5}{8}

Schritte zur Lösung

y^{'} (t) = 8 y - 5

Solve separable ODE:

y = \frac{e ^{8 t + c_{1}}}{8} + \frac{5}{8}

y = \frac{e ^{8 t + c_{1}}}{8} + \frac{5}{8}

\frac{d y}{d t} = (2 y + 1)

2 x y y^{^{'}} = 2, x^{2} + 1 = 0

\frac{d y}{d x} 3^{x} + 3^{y} = 3^{x + y}

\frac{d y}{d x} = e^{x + 2 y}, y (0) = \frac{1}{2}

y^{^{'}} + 5 y = 9