What is the solution for (dy)/(dx)+(e^{x/2})/(25e^{5y)}=0 ?

The solution for (dy)/(dx)+(e^{x/2})/(25e^{5y)}=0 is y=(ln((-2e^{x/2}+c_{1})/5))/(5)

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(dy)/(dx)+(e^{x/2})/(25e^{5y)}=0

\frac{d y}{d x} + \frac{e ^{\frac{x}{2}}}{25 e ^{5 y}} = 0

y = \frac{ln ( \frac{- 2 e ^{\frac{x}{2}} + c _{1}}{5} )}{5}

Solution steps

\frac{d y}{d x} + \frac{e ^{\frac{x}{2}}}{25 e ^{5 y}} = 0

Solve separable ODE:

y = \frac{ln ( \frac{- 2 e ^{\frac{x}{2}} + c _{1}}{5} )}{5}

y = \frac{ln ( \frac{- 2 e ^{\frac{x}{2}} + c _{1}}{5} )}{5}

What is the solution for (dy)/(dx)+(e^{x/2})/(25e^{5y)}=0 ?
The solution for (dy)/(dx)+(e^{x/2})/(25e^{5y)}=0 is y=(ln((-2e^{x/2}+c_{1})/5))/(5)