(dx)/(dt)+x=0

Lösung

\frac{d x}{d t} + x = 0

x = e^{- t + c_{1}}

Schritte zur Lösung

\frac{d x}{d t} + x = 0

Solve separable ODE:

x = e^{- t + c_{1}}

x = e^{- t + c_{1}}

\frac{d y}{5 x + 2} - \frac{d x}{2 y - 1} = 0

y^{^{'}} + 0.5 y = 1

y^{^{'}} + t y = y, y (1) = 3

\frac{d x}{d t} = e^{t - x}

\frac{d y}{d x} = \frac{7 x}{e ^{y}}