(x^2+25)y^'=xy

Lösung

(x^{2} + 25) y^{^{'}} = x y

y = c_{1} x^{2} + 25

Schritte zur Lösung

(x^{2} + 25) y^{'} (x) = x y

Solve separable ODE:

y = c_{1} x^{2} + 25

y = c_{1} x^{2} + 25

x^{2} \frac{d y}{d x} + \frac{1}{x} y = \frac{2}{x} y^{- 3}

\frac{d x}{d y} = 1 - 0.4 x

y^{^{'}} - x^{2} cos (y) = x^{2}

y^{^{'}} = y^{2} x^{2}

\frac{d y}{d x} = 8 x sec (y)