dv=sin(x)dx

Lösung

d v = sin (x) d x

x = arccos (- v - c_{1}) + 2 πn, x = - arccos (- v - c_{1}) + 2 πn

Schritte zur Lösung

d v = sin (x) d x

Solve separable ODE:

x = arccos (- v - c_{1}) + 2 πn, x = - arccos (- v - c_{1}) + 2 πn

x = arccos (- v - c_{1}) + 2 πn, x = - arccos (- v - c_{1}) + 2 πn

\frac{d x}{d t} = 1 - x

2 x y^{3} d x + 3 x^{2} y^{2} d y = 0, y (1) = 2

5 x \frac{d y}{d x} = 6 (7 - 3 y)

\frac{d y}{d x} = 3 x^{6} y, y > 0

y^{^{'}} - 2 y = 2 y^{\frac{1}{2}}, y (0) = 1