ydx+(1-x)dy=0

Lösung

y d x + (1 - x) d y = 0

y = e^{c_{1}} - e^{c_{1}} x

Schritte zur Lösung

y d x + (1 - x) d y = 0

Solve separable ODE:

y = e^{c_{1}} - e^{c_{1}} x

y = e^{c_{1}} - e^{c_{1}} x

(e^{x} + x) y d y - e^{y} d x = 0

cos (y) sin (t) \frac{d y}{d t} = sin (y) cos (t)

\frac{y ^{^{'}}}{t} = 3 y^{2} + 2 y + 1

\frac{d v}{d x} = - 475000 - 5 v^{2}

y^{^{'}} - 9 y = 0