y^'=x^3y^3

Lösung

y^{^{'}} = x^{3} y^{3}

y = - \frac{2}{x ^{4} + c _{1}}, y = - - \frac{2}{x ^{4} + c _{1}}

Schritte zur Lösung

y^{'} (x) = x^{3} y^{3}

Solve separable ODE:

y = - \frac{2}{x ^{4} + c _{1}}, y = - - \frac{2}{x ^{4} + c _{1}}

y = - \frac{2}{x ^{4} + c _{1}}, y = - - \frac{2}{x ^{4} + c _{1}}

d x - (8 x y + 3 y) d y = 0

\frac{d y}{d x} = \frac{y}{2 x + 1}

y^{^{'}} - a^{2} k y + b^{2} = 0

y^{^{'}} - 2 t y^{3} = 0

\frac{d y}{d t} = - k y