d/(dθ)(r(θ))+r(θ)tan(θ)=3tan(θ)

Lösung

\frac{d r}{d θ} + r tan (θ) = 3 tan (θ)

r = \frac{3 tan ( θ )}{1 + tan ( θ ) θ}; 1 + tan (x) x \neq = 0

Schritte zur Lösung

\frac{d}{d θ} (r θ) + r θ tan (θ) = 3 tan (θ)

\frac{d}{d θ} (r θ) = r

r + r θ tan (θ) = 3 tan (θ)

r + r θ tan (θ) = 3 tan (θ) : r = \frac{3 tan ( θ )}{1 + tan ( θ ) θ}; 1 + tan (x) x \neq = 0

r = \frac{3 tan ( θ )}{1 + tan ( θ ) θ}; 1 + tan (x) x \neq = 0

(x + 1) \frac{d y}{d x} = 2 y

\frac{d v}{d t} = - 0.4 \cdot v

\frac{d y}{d t} = \frac{2 t}{y + y t ^{2}}

y^{^{'}} = x^{3} e^{- y}

y^{^{'}} = y^{2} + 4