y^2dx+dy=0

Lösung

y^{2} d x + d y = 0

y = - \frac{1}{- x + c _{1}}

Schritte zur Lösung

y^{2} d x + d y = 0

Solve separable ODE:

y = - \frac{1}{- x + c _{1}}

y = - \frac{1}{- x + c _{1}}

v^{2} y^{2} d y + v y^{3} d v + 2 v^{2} y^{2} d y + y^{2} d y = 0

\frac{d y}{d x} = 3 y - 1

\frac{d x}{d y} = e^{2 x + 3 y}

y^{^{'}} + 5 y = 20

y^{^{'}} = y^{2} (x + 1)