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Frequently Asked Questions (FAQ)
What is the solution for y^{'''}-3y^{''}+3y^'-y=x-3e^x ?
- The solution for y^{'''}-3y^{''}+3y^'-y=x-3e^x is y=c_{1}e^x+c_{2}xe^x+c_{3}x^2e^x-x-3-(e^xx^3)/2