x^2y^3y^'=2x^3y

解答

x^{2} y^{3} y^{^{'}} = 2 x^{3} y

y = 3 3 x^{2} + c_{1}

求解步骤

x^{2} y^{3} y^{'} (x) = 2 x^{3} y

求解可分离方程:

y = 3 3 x^{2} + c_{1}

y = 3 3 x^{2} + c_{1}

\frac{d y}{d x} = 8 x (y^{2} + 1)

\frac{d y}{d t} = 6 y t^{2}

x^{^{'}} - a x = 0

\frac{d y}{d t} + 2 y = 6, y (0) = 0

3 y + 5 + (3 x - 3) \frac{d y}{d x} = 0