(4dy)/((x^2+1)dx)= 1/(2y)

Lösung

\frac{4 d y}{( x ^{2} + 1 ) d x} = \frac{1}{2 y}

y = \frac{x ^{3} + 3 x + c _{1}}{2 3}, y = - \frac{x ^{3} + 3 x + c _{1}}{2 3}

Schritte zur Lösung

\frac{4 d y}{( x ^{2} + 1 ) d x} = \frac{1}{2 y}

Solve separable ODE:

y = \frac{x ^{3} + 3 x + c _{1}}{2 3}, y = - \frac{x ^{3} + 3 x + c _{1}}{2 3}

y = \frac{x ^{3} + 3 x + c _{1}}{2 3}, y = - \frac{x ^{3} + 3 x + c _{1}}{2 3}

2 y y^{^{'}} = 3 x^{2}

(1 + y + y^{2}) d x + x (x^{2} - 4) d y = 0

\frac{d y}{d t} = 12 y t^{2}

x y^{^{'}} + 6 y = 0

x^{2} y^{^{'}} + \frac{1}{y ^{2}} = 0, y (1) = 2