y^'=ysqrt(y^2-1)

Lösung

y^{^{'}} = y y^{2} - 1

y = tan^{2} (t + c_{1}) + 1, y = - tan^{2} (t + c_{1}) + 1

Schritte zur Lösung

y^{'} (t) = y y^{2} - 1

Solve separable ODE:

y = tan^{2} (t + c_{1}) + 1, y = - tan^{2} (t + c_{1}) + 1

y = tan^{2} (t + c_{1}) + 1, y = - tan^{2} (t + c_{1}) + 1

(x - 3) y^{^{'}} + 2 y = 0

\frac{d y}{d x} - \frac{y}{3 x - 1} = 0

y^{^{'}} + x y = x y^{- \frac{1}{2}}

\frac{d z}{d t} + 2 e^{t + z} = 0

\frac{d y}{d x} = 3 x^{2} y, y (1) = 1