x^2sin(x)dx+xydy=0

Lösung

x^{2} sin (x) d x + x y d y = 0

y = 2 x cos (x) - 2 sin (x) + c_{1}, y = - 2 x cos (x) - 2 sin (x) + c_{1}

Schritte zur Lösung

x^{2} sin (x) d x + x y d y = 0

Solve separable ODE:

y = 2 x cos (x) - 2 sin (x) + c_{1}, y = - 2 x cos (x) - 2 sin (x) + c_{1}

y = 2 x cos (x) - 2 sin (x) + c_{1}, y = - 2 x cos (x) - 2 sin (x) + c_{1}

\frac{d y}{d x} - 4 x y = x

\frac{d V}{d t} = 1 - 0.4 V

2 x y^{^{'}} + y = 1

y^{^{'}} = \frac{3 y ^{2}}{2 x}

1 - y^{2} d x = (1 + x^{2}) y d y