integral of 0.8sin(x)+(1.6)/(pi^2)x

解

\int 0.8 sin (x) + \frac{1.6}{π ^{2}} x d x

- 0.8 cos (x) + 0.08105 \dots x^{2} + C

解答ステップ

\int 0.8 sin (x) + \frac{1.6}{π ^{2}} x d x

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 0.8 sin (x) d x + \int \frac{1.6}{π ^{2}} x d x

\int 0.8 sin (x) d x = - 0.8 cos (x)

\int \frac{1.6}{π ^{2}} x d x = 0.08105 \dots x^{2}

= - 0.8 cos (x) + 0.08105 \dots x^{2}

定数を解答に追加する

= - 0.8 cos (x) + 0.08105 \dots x^{2} + C