d/(dθ)(-n/2ln(2pi)-n/2ln(θ^2))

Lösung

\frac{d}{d θ} (- \frac{n}{2} \cdot ln (2 π) - \frac{n}{2} \cdot ln (θ^{2}))

- \frac{n}{θ}

Schritte zur Lösung

\frac{d}{d θ} (- \frac{n}{2} ln (2 π) - \frac{n}{2} ln (θ^{2}))

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d θ} (\frac{n}{2} ln (2 π)) - \frac{d}{d θ} (\frac{n}{2} ln (θ^{2}))

\frac{d}{d θ} (\frac{n}{2} ln (2 π)) = 0

\frac{d}{d θ} (\frac{n}{2} ln (θ^{2})) = \frac{n}{θ}

= - 0 - \frac{n}{θ}

Vereinfache

= - \frac{n}{θ}

x \to 0 lim (\frac{7}{2 x})

\int 100 - 2 x d x

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