derivative of \sqrt[7]{x^4}

Lösung

\frac{d}{d x} (7 x^{4})

\frac{4}{7 x ^{\frac{3}{7}}}

Schritte zur Lösung

\frac{d}{d x} (7 x^{4})

Wende die Kettenregel an:

\frac{1}{7 ( x ^{4} ) ^{\frac{6}{7}}} \frac{d}{d x} (x^{4})

= \frac{1}{7 ( x ^{4} ) ^{\frac{6}{7}}} \frac{d}{d x} (x^{4})

\frac{d}{d x} (x^{4}) = 4 x^{3}

= \frac{1}{7 ( x ^{4} ) ^{\frac{6}{7}}} \cdot 4 x^{3}

Vereinfache

\frac{1}{7 ( x ^{4} ) ^{\frac{6}{7}}} \cdot 4 x^{3} : \frac{4}{7 x ^{\frac{3}{7}}}

= \frac{4}{7 x ^{\frac{3}{7}}}

\int (e^{x} - 1) d x

\int_{0}^{1} \frac{1 + 12 x}{1 + 3 x} d x

\frac{d}{d x} (x^{2} - 3 x + 1)

x \to 0 lim (e^{- 3 x})

d er i v a t i v e y = \frac{9 ( 1 - sin ( x ) )}{2 cos ( x )}