sum from n=0 to infinity of (1+2/(5n))^2

Lösung

n = 0 \sum \infty (1 + \frac{2}{5 n})^{2}

divergiert

Schritte zur Lösung

n = 1 \sum \infty (1 + \frac{2}{5 n})^{2}

Seriendivergenztest anwenden:

divergiert

= divergiert

n = 1 \sum \infty \frac{1}{1 + n ^{3}}

n = 0 \sum \infty \frac{1}{1000 n + 1}

n = 4 \sum \infty \frac{6 ^{n}}{n !}

n = 2 \sum \infty \frac{1}{n} - \frac{1}{n - 1}

n = 1 \sum \infty \frac{1}{4 n + 1}