Solution

Solution

Solution steps
Apply the constant multiplication rule:
Apply Series Integral Test:diverges

Popular Examples

sum from n=2 to infinity of (-0.65)^nsum from n=1 to infinity of 1/5sum from n=1 to infinity of (n+1)/(3^n)sum from n=0 to infinity of 2/nsum from n=1 to infinity of (6^n)/(n!)

Frequently Asked Questions (FAQ)

  • What is the sum from n=1 to infinity of 6/(n+3) ?

    The sum from n=1 to infinity of 6/(n+3) is diverges