integral from-1 to 1 of 2-x^2

解答

\int_{- 1}^{1} 2 - x^{2} d x

\frac{10}{3}

十进制

3.33333 \dots

求解步骤

\int_{- 1}^{1} 2 - x^{2} d x

使用积分加法定则:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} 2 d x - \int_{- 1}^{1} x^{2} d x

\int_{- 1}^{1} 2 d x = 4

\int_{- 1}^{1} x^{2} d x = \frac{2}{3}

= 4 - \frac{2}{3}

化简

4 - \frac{2}{3} : \frac{10}{3}

= \frac{10}{3}

\int_{- 1}^{2} x^{2} - 2 x d x

t a y l or (1 + x)^{n} 0

\frac{d}{d x} (\frac{2 x ^{2} - 3 x}{x - 2})

\frac{\partial}{\partial x} (6 y + 1)

x \to 0 - lim (sin (\frac{π}{x}))