What is the limit as x approaches 1-of-1/(x^2+6x-7) ?

The limit as x approaches 1-of-1/(x^2+6x-7) is infinity

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limit as x approaches 1-of-1/(x^2+6x-7)

x \to 1 - lim (- \frac{1}{x ^{2} + 6 x - 7})

\infty

Solution steps

x \to 1 - lim (- \frac{1}{x ^{2} + 6 x - 7})

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= - x \to 1 - lim (\frac{1}{x ^{2} + 6 x - 7})

For

x

approaching

1

from the left

, x < 1 \Rightarrow x^{2} + 6 x - 7 < 0

The denominator is a negative quantity approaching 0 from the left

= - (- \infty)

Simplify

= \infty

x \to 0 lim (ln (\frac{x ^{2}}{2}))

θ \to + 0 lim (\frac{sin ( 30 )}{θ})

x \to \infty lim (\frac{1}{x} \cdot 0)

x \to 0 lim (x (\frac{2}{x}))

x \to - 2 lim (\frac{x ^{3} + 8}{x + 8})

What is the limit as x approaches 1-of-1/(x^2+6x-7) ?
The limit as x approaches 1-of-1/(x^2+6x-7) is infinity