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人気のある微分積分 >

limit as x approaches 1+of-ln(x^2-1)

解

x \to 1 + lim (- ln (x^{2} - 1))

解

\infty

解答ステップ

x \to 1 + lim (- ln (x^{2} - 1))

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= - x \to 1 + lim (ln (x^{2} - 1))

連鎖法則の制限を適用する:

- \infty

= - (- \infty)

簡素化

= \infty

グラフ

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