derivative of 3x^2+e^{2x}+pi^2

Lösung

\frac{d}{d x} (3 x^{2} + e^{2 x} + π^{2})

6 x + 2 e^{2 x}

Schritte zur Lösung

\frac{d}{d x} (3 x^{2} + e^{2 x} + π^{2})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (e^{2 x}) + \frac{d}{d x} (π^{2})

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (e^{2 x}) = e^{2 x} \cdot 2

\frac{d}{d x} (π^{2}) = 0

= 6 x + e^{2 x} \cdot 2 + 0

Vereinfache

= 6 x + 2 e^{2 x}

n = 1 \sum \infty \frac{n}{6 n ^{2} - 5}

x \to + 4 - lim (\frac{2 x}{16 - x ^{2}})

\int (3 x + 2 e^{x})^{2} d x

\frac{\partial}{\partial x} (5 9 x^{2} + 16 y^{2})

\int \frac{7}{x ( x ^{2} + 25 )} d x