(\partial)/(\partial z)(xz-7yz+4)

解答

\frac{\partial}{\partial z} (x z - 7 yz + 4)

x - 7 y

求解步骤

\frac{\partial}{\partial z} (x z - 7 yz + 4)

将

x, y

视为常数

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial z} (x z) - \frac{\partial}{\partial z} (7 yz) + \frac{\partial}{\partial z} (4)

\frac{\partial}{\partial z} (x z) = x

\frac{\partial}{\partial z} (7 yz) = 7 y

\frac{\partial}{\partial z} (4) = 0

= x - 7 y + 0

化简

= x - 7 y

\int e^{- s t} cos (2 t) d t

d er i v a t i v e x^{2} + 3

d er i v a t i v e 2 x^{3} 25 - x^{2}

x \to 0 + lim (1)

x \to 1 lim (\frac{e ^{x}}{x - 1})