integral from-1 to 1 of 2x^2-x+6

Lösung

\int_{- 1}^{1} 2 x^{2} - x + 6 d x

\frac{40}{3}

Dezimale

13.33333 \dots

Schritte zur Lösung

\int_{- 1}^{1} 2 x^{2} - x + 6 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} 2 x^{2} d x - \int_{- 1}^{1} x d x + \int_{- 1}^{1} 6 d x

\int_{- 1}^{1} 2 x^{2} d x = \frac{4}{3}

\int_{- 1}^{1} x d x = 0

\int_{- 1}^{1} 6 d x = 12

= \frac{4}{3} - 0 + 12

Vereinfache

\frac{4}{3} - 0 + 12 : \frac{40}{3}

= \frac{40}{3}

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