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人気のある微分積分 >

integral from 0 to pi of (1-cos(2x))

解

\int_{0}^{π} (1 - cos (2 x)) d x

解

π

+1

十進法表記

3.14159 \dots

解答ステップ

\int_{0}^{π} 1 - cos (2 x) d x

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{π} 1 d x - \int_{0}^{π} cos (2 x) d x

\int_{0}^{π} 1 d x = π

\int_{0}^{π} cos (2 x) d x = 0

= π - 0

簡素化

= π

グラフ

人気の例

integral from 0 to 2 of 1/((2-x)^2)

\int_{0}^{2} \frac{1}{( 2 - x ) ^{2}} d x

integral from 0 to 5/4 of sqrt(1+9x)

\int_{0}^{\frac{5}{4}} 1 + 9 x d x

integral from 4 to 4.5 of (6-x)/6

\int_{4}^{4.5} \frac{6 - x}{6} d x

integral from 51 to 100 of 1/x

\int_{51}^{100} \frac{1}{x} d x

integral from 0 to pi of sin^2(θ)sin(θ)

\int_{0}^{π} sin^{2} (θ) sin (θ) d θ