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人気のある微分積分 >

integral from 1/2 to 1 of (sin(x))/x

解

\int_{\frac{1}{2}}^{1} \frac{sin ( x )}{x} d x

解

0.9460830704 - Si (\frac{1}{2})

解答ステップ

\int_{\frac{1}{2}}^{1} \frac{sin ( x )}{x} d x

非初等積分を使用する:

\int \frac{sin ( x )}{x} d x = Si (x)

= [Si (x)]_{\frac{1}{2}}^{1}

限度を計算する:

0.9460830704 - Si (\frac{1}{2})

= 0.9460830704 - Si (\frac{1}{2})

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